Constructions (Circles)

341. Tangents from the Outside · equal lengths, perfect right angles

PA and PB are always equal in length, and both meet the circle at exactly 90°.

OABPA = 316.2PA = 316.2PB = 316.2PB = 316.2P
The two tangents from an external point P are equal in length (PA = PB), and each is perpendicular to the radius at its point of contact (90° at A and B). OP bisects the angle between them.

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For subscribers · Selina ICSE: Constructions (Circles)

What this lesson covers

Try to break it

Drag P around outside the circle. The two tangent lines from P always come out equal in length (PA = PB), and each meets its radius at 90°. Pull P inside the circle and the construction can't draw tangents — no line through an interior point can touch the circle at exactly one place.

How you build it

Construct the two tangents from an external point P, and see that PA = PB with each meeting the circle at 90°.

  • Point tool: mark O near the middle — the centre of the circle.
  • Circle tool: click O as the centre, then click outward to set the radius.
  • Point tool: mark P well outside the circle — the external point.
  • Segment tool: join the centre O to the external point P.
  • Bisector tool: click O then P — it draws the perpendicular bisector of OP, crossing OP at its midpoint.
  • Point tool: mark M where the perpendicular bisector crosses OP — the midpoint of OP.
  • Circle tool: click M as the centre, then click O — this circle has OP as its diameter and cuts the main circle at the points of contact.
  • Point tool: mark A at one point where the construction circle meets the main circle.
  • Point tool: mark B at the other crossing of the two circles.
  • Segment tool: join P to A — the first tangent.
  • Segment tool: join P to B — the second tangent. Because A and B lie on the circle with diameter OP, ∠OAP = ∠OBP = 90°, so PA and PB are tangents — and PA = PB.

The proof, step by step

Prove that the two tangents constructed from the external point are equal and meet the circle at right angles to the radius.

  • A and B lie on the circle with diameter OP.
  • ∠PAO = 90° and ∠PBO = 90° (Angles in a semicircle).
  • OA ⊥ PA and OB ⊥ PB.
  • PA and PB are tangents (perpendicular to radius at endpoint).

Worked example

From an external point P, a tangent PT is drawn to a circle with centre O and radius 5 cm. If OP = 13 cm, find the length of PT.

In right triangle OTP (right-angled at T), PT² = OP² - OT² = 13² - 5² = 169 - 25 = 144. Thus, PT = √144 = 12 cm.

  • 12 cm — correct
  • 8 cm
  • 10 cm
  • 13 cm

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