Reflection (In x-axis, y-axis, x = a, y = a and the origin; Invariant Points)

298. Mirror Through the Origin · Flip both signs, keep the distance

O is always the midpoint of PP', and P' is always (-x, -y) relative to O.

xyOP(x, y)P'(-x, -y)PO = 228PO = 228OP' = 228OP' = 228P
Reflecting in the origin sends (x, y) → (−x, −y) — both signs change. The origin O is the midpoint of the segment joining each point to its image.

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For subscribers · Selina ICSE: Reflection (In x-axis, y-axis, x = a, y = a and the origin; Invariant Points)

What this lesson covers

Try to break it

Drag P anywhere. P' always lands at (−x, −y) — both coordinates flip. The origin O is the midpoint of PP', and OP = OP' at every position. Drag P to the origin and P' lands on top of P; the only fixed point of reflection through O is O itself.

How you build it

Reflect a point in the origin.

  • Place point P. Its reflection P' will appear automatically.

The proof, step by step

Prove that reflection in the origin maps P(x, y) to P prime(−x, −y).

  • Let P be (x, y) and O be (0, 0).
  • By definition of reflection in origin, O is the midpoint of PP'.
  • Midpoint formula: ((x + x')/2, (y + y')/2) = (0, 0).
  • Solving gives x' = -x and y' = -y.
  • Hence, P' is (-x, -y).

Worked example

If point A(3, -4) is reflected in the origin, what are the coordinates of its image A'?

Reflection in the origin negates both coordinates. A(3, -4) becomes A'(-3, 4).

  • A'(3, 4)
  • A'(-3, 4) — correct
  • A'(-3, -4)
  • A'(4, -3)

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